0=3t^2+24t+48

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Solution for 0=3t^2+24t+48 equation:



0=3t^2+24t+48
We move all terms to the left:
0-(3t^2+24t+48)=0
We add all the numbers together, and all the variables
-(3t^2+24t+48)=0
We get rid of parentheses
-3t^2-24t-48=0
a = -3; b = -24; c = -48;
Δ = b2-4ac
Δ = -242-4·(-3)·(-48)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{24}{-6}=-4$

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